in a transistor amplifier, when the signal charges by 0.02V, the base current changes by 10MA and collector current 12IMA. if collector load RC=5Kohms and RL=10Kohms, find (1) current gain (2) input Impedance (3) A. C load (4) Voltage gain (5) power gain

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electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j