A bicyclist initially at rest, begins pedaling and gained speed steadily for 4.80s during which she covers 37.0m What was her final speed?

The final speed of the bicyclist is 15.44 m/s.

Explanation:

Given;

initial velocity, u = 0

time of motion, t = 4.8 s

distance covered, d = 37.0 m

The acceleration of the bicyclist is calculated as;

d = ut + ¹/₂at²

37 = 0 + ¹/₂(4.8)²a

37 = 11.52a

a = 37 / 11.5

a = 3.22 m/s²

The final speed of the bicyclist is given as;

v² = u² + 2ad

v² = 0 + 2(3.22)(37)

v² = 238.28

v = √238.28

v = 15.44 m/s

Therefore, the final speed of the bicyclist is 15.44 m/s.