Object A has 27 J of kinetic energy. Object B has one-quarter the mass of object A. *By what factor does the speed of each object change if total work -18 J is done on each?

the final speed of object A changed by a factor of   = 0.58

the final speed of object B changed by a factor of = 1.29

Explanation:

Given;

kinetic energy of object A, = 27 J

let the mass of object A =

then, the mass of object B =

work done on object A = -18 J

work done on object B = -18 J

let be the initial speed

let be the final speed

For object A;

Thus, the final speed of object A changed by a factor of   = 0.58

To obtain the change in the final speed of object B, apply the following equations.

Thus, the final speed of object B changed by a factor of = 1.29

since you're a real machine, your ama is always less than your ima, because you can never totally eliminate friction.

12000j is work done