A 1.13 kg skateboard is coasting along the pavement at a speed of 4.28 m/s when a 0.93 kg cat drops from a tree vertically downward onto the skateboard. What is the speed of the
skateboard-cat combination?

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

Domain eukarya; kingdom plantae should be the answer.