A 200-gram baseball traveling at 48 m/s is hit by a bat and rebounds in the opposite direction at 52 m/s. Find the average force of the bat on the ball if the time of contact is 2.0x10-3 s.

400N

Explanation:

Given the following parameters

Mass m = 200g = 0.2kg

initial velocity u = 48m/s

Final velocity v = 52m/s

Time t = 2.0x10-3 s.

Impulse is expressed as I = Ft = m(v-u)

Ft = m(v-u)

F =  m(v-u)/t

Substitute the given values into the formula

F = 0.2(52-48)/0.002

F = 0.2(4)/0.002

F = 0.8/0.002

F = 400N

Hence the average force of the bat on the ball is 400N

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