With the help of the given diagram calculate the current through each resistor.

2 and 0.6 ohms = 1.8A

4ohms = 1.08A

6 ohms = 0.72 ohms

Explanation:

With the help of the given diagram calculate the current through each resistor.

According to ohms law

E = IRt

E is the electromotive force = 9V

I is the total current in the circuit

Rt is the total equivalent resistance

Get Rt

1/R = (1/4+1/6)  (parallel resistors)

1/R = 3+2/12

1/R = 5/12

R = 12/5

R = 2.4 ohms

Rt = 2 + 0.6 + 2.4

Rt = 5 ohms

Get the total current

I = E/Rt

I = 9/5

I = 1.8A

Since same current flows in a series connected resistors

Current in the 2 and 0.6 ohms resistors will be 1.8A

For the 4 and 6 ohms resistor:

Voltage across them is expressed as:

V = IR

V = 1.8(2.4)

V = 4.32Volts

The current in 4 ohms resistor

I = 4.32/4

I = 1.08A

The current in 6 ohms resistor

I = 4.32/6

I = 0.72A

it has to be b, about 97 percent.

god i hope this !