I'll give brainliest . a train starts from rest and moves with a uniform acceleration of x metre per second square for 5 minutes determine the value of x if it covers a distance of 5.8 km during the journey

x = ~0.1289 m/s^2

Explanation:

We can use one of the kinematic formulas. We see that the equation doesn’t contain the final velocity, so we use the kinematic equation d = v_0t + (1/2)at^2.

Since the train started from rest, the initial velocity, v_0, is 0. Thus, the equation becomes:

d = (1/2)at^2

Note that 5 minutes is 300 seconds and 5.8 km is 5800 m. Substituting the values we are given, we get:

5800 m = (1/2)(x m/s^2)(300 s)^2 = (45000 s^2)(x m/s^2)

Dividing by 45,000 on both sides, we get:

x = ~0.1289 m/s^2

I hope this helps! :)

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

don't remove my answer im trying my best to answer them

explanation: