A car accidentally rolls off cliff as it leaves the cliff it has a horizontal velocity of 13 m/s it hits the ground 60 m from the shoreline calculate the height of the cliff

The height of the cliff from which the car rolls off is 104.59 m

We'll begin by calculating the the time taken for the car to reach the ground.

Horizontal distance (s) = 60 m

Horizontal velocity (u) = 13 m/s

t = 4.62 s

Thus, the time taken for the car to reach the ground is 4.62 s

Time (t) = 4.62 s

Acceleration due to gravity (g) = 9.8 m/s²

h = ½gt²

h = ½ × 9.8 × 4.62²

Therefore, the height of the cliff is 104.59 m

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h = 104.13 m

Explanation:

Given that,

Horizontal velocity of the car, v = 13 m/s

It hits the ground 60 m from the shoreline

We need to find the height of the cliff. Let t be the time of fall. We can find it as follows :

So, the time of fall is 4.61 seconds.

Let h is the height of the cilff. Using second equation of motion to find it as follows :

So, the height of the cliff is 104.13 m.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .

float.

archimedes' principle

denser than water sinks in water.

denser than mercury would sink in it