A basketball is rolling rightward onto the court with a speed of 4.0 m/s and slows down with a consta leftward acceleration of magnitude 0.50 m/s^2 over 14 m. What is the velocity of the basketball after rolling for 14 m?
a. 2.0 m/s
b. 5.5 m/s
c. 7.5 m/s
d. 1.4 m/s

d. 1.4 m/s

Explanation:

Given;

initial velocity of the `basketball, u = 4.0 m/s

acceleration of the basketball, a = -0.5 m/s² (leftward)

distance the basketball traveled, d = 14 m

the final velocity of the basketball, v = ?

(this final velocity should be less than the initial velocity since the ball is slowing down at a constant rate)

Apply the following the kinematic equation;

v² = u² + 2ad

v² = 4² + 2(-0.5)14

v² = 16 - 14

v² = 2

v = √2

v = 1.41 m/s

Therefore, the final velocity of the basketball is 1.4 m/s.