If the evaporator outlet temperature on an r410A system is 50f and the evaporator superheat is 10f, what is the evaporating pressure of the refrigerant in the system

So, the evaporating pressure of the R410A = 118 psig

Explanation:

Solution:

For R410A system:

Data Given:

Evaporator Outlet Temperature = 50°F

Evaporator Superheat = 10°F

Required:

Evaporating Pressure in the system = ?

For this, first of all, we need to calculate inlet temperature on R410A system from the given value of outlet temperature.

Evaporator inlet temperature is the difference of outlet temperature and evaporator superheat.

Evaporator inlet temperature = Outlet Temperature - Evaporator Superheat

Evaporator inlet Temperature = 50°F - 10°F

Evaporator inlet Temperature = 40°F

Now, as we have the inlet temperature and the R410A system. We can consult the pressure temperature chart or PT chart, which I have attached and highlighted the value of evaporating pressure for 40°F inlet temperature.

So, the evaporating pressure of the R410A = 118 psig

The answer is water molecules are split.cellular respiration and photosynthesis are complement  reactions to each other. these are reverse reactions. in cellular respiration glucose and oxygen yield water and carbon dioxide. so, when respiration begins,  glucose molecules are split. in the opposite reaction - in photosynthesis, carbon dioxide and water yield glucose and oxygen. thus,  when respiration begins, water molecules are split.

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