the block of wood is placed on a rough horizontal plane. if the friction between the block and the plane is 6n ,what is the work done to move the block througha distance of 1.5m?

Gravitation for exert on block along slope = Mgsin30

Since net force is 0 (constant speed)

Frictional force = Mgsin30

C(friction) = Frictional Force/Normal Force

Normal Force = Mgcos30

C(friction) = Frictional Force/Normal Force

=Mgsin30/Mgcos30

= tan 30

=0.577

Explanation:

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg