4. A physics student with a mass m is running with a speed V, and jumps onto a skateboard that has 1/4 the mass of the student. What is the speed of the student-skateboard system after the student has
landed on the skateboard?

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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you can cut your hand off if your not