A plane starting from rest accelerates to takeoff velocity of 75 m/s in 15
seconds. What was the plane’s
acceleration and how far did it travel
before takeoff?

The acceleration is 5 m/s² and the distance is 562.5  m.

Explanation:

Given that,

Initial velocity of the plane, u = 0 (at rest)

Final speed, v = 75 m/s

Time, t = 15 s

We need to find the acceleration of the plane and distance it travel before takeoff.

Let the distance is d.

So, the acceleration is 5 m/s² and the distance is 562.5  m.

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force