Not allowed to use kinematics

A. 131.9 s

B. 0.13 m/s

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 490 Kg

Height (h) = 17 m

Power (P) = 0.83 hp

Time (t) =?

Velocity (v) =.?

Next, we shall convert 0.83 hp to Watts. This can be obtained as follow:

1 hp = 745.7 Watts

Therefore,

0.83 hp = 0.83 hp × 745.7 Watts / 1 hp

0.83 hp = 618.931 Watts

Thus, 0.83 hp is equivalent to 618.931 Watts.

A. Determination of the time.

Mass (m) = 490 Kg

Height (h) = 17 m

Power (P) = 618.931 Watts

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

Power = Energy / time

P = mgh / t

618.931 = 490 × 9.8 × 17 / t

618.931 = 81634 / t

Cross multiply

618.931 × t = 81634

Divide both side by 618.931

t = 81634 / 618.931

t = 131.9 s

Therefore, it will take 131.9 s to lift the beam.

B. Determination of the constant velocity.

We'll begin by calculating the force. This can be obtained as follow:

Mass (m) = 490 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) =?

Force = mass × acceleration

Force = 490 × 9.8

Force = 4802 N

Finally, we shall determine the constant velocity as follow:

Force (F) = 4802 N

Power (P) = 618.931 Watts

Velocity (v) =?

P = F × v

618.931 = 4802 × v

Divide both side by 4802

v = 618.931 / 4802

v = 0.13 m/s

Thus, the constant speed at which the beam moves upward is 0.13 m/s

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