the weight of a piece of stone when fully immersed in water is 18N and it displaces 4N of water. what is the weight of the stone in air?

4N

Explanation:

Given parameters:

Weight of stone when immersed in water  = 18N

Weight of water displaced  = 4N

Unknown:

Weight of the stone in air  = ?

Solution:

To solve this problem, we employ the Archimedes' principles.

It states that the upward buoyant force on a body is equal to the weight of the fluid displaced.

The weight of the water displaced is equal to the weight of the body.

So, the weight of the stone in air  = 4N

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever