Question 3 of 32 A man is trying to drag a small tree that he cut down. If the static coefficient
of friction of the tree on the ground is 0.5 and the tree weighs 670 N, what is
the minimum amount of horizontal force that the man will need to apply so
that the tree will start moving?
A. 465 N
B. 670 N
C. 335 N
D. 230 N

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.