A 100 kilowatt bulb burns for 3 hours how much energy did it use

1.08×10⁹ J

Explanation:

From the question given above, the following data were obtained:

Power (P) = 100 kilowatt

Time (t) = 3 hours

Energy (E) =?

Next, we shall convert 100 kilowatt to Watts. This can be obtained as follow:

1 KW = 1000 W

Therefore,

100 KW = 100 KW × 1000 W / 1 KW

100 KW = 100000 W

Thus, 100 KW is equivalent to 100000 W.

Next, we shall convert 3 hrs to second (s). This can be obtained as follow:

1 h = 3600 s

Therefore,

3 h = 3 h × 3600 s / 1 h

3 h = 10800 s

Thus, 3 h is equivalent to 10800 s.

Finally, we shall determine the amount of energy consumed as follow:

Power (P) = 100000 W

Time (t) = 10800 s

Energy (E) =?

P = E/t

100000 = E / 10800

Cross multiply

E = 100000 × 10800

E = 1.08×10⁹ J

Therefore, 1.08×10⁹ J of energy was consumed.

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