In a copper wire that has a diameter of 1.63 mm, the drift velocity is 7.08x10^-4 m/s. Assume that there is one free electron for conduction per copper atom. Copper has an atomic mass of 1.055x10^-25 kg and a density of about 9 g/cm^3. Required:
a. What is the current in the wire?
b. What is the current density?

(a). The current in the wire is 20.16 A.

(b). The current density is 9.66 A/mm².

Explanation:

Given that,

Diameter = 1.63 mm

Drift velocity

Atomic mass of copper

Atomic weight of copper =63.5 g

Density = 9 g/cm³  

We need to calculate the number density of electron

Using formula of number density

Where, w= atomic weight

Put the value into the formula

(a).We need to calculate the current in the wire

Using formula of drift velocity

Where, A = cross section area

q = charge of electron

n = number density of electron

= drift velocity

Put the value into the formula

(b). We need to calculate the current density

Using formula of current density

Put the value into the formula

Hence, (a). The current in the wire is 20.16 A.

(b). The current density is 9.66 A/mm².

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

-reverse card

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.