How much heat is needed to raise the temperature of 4.68kg of lead from 25.0c to 62.0

22510.8J

Explanation:

Given parameters:

Mass of lead  = 4.68kg

Initial temperature  = 25°C

Final temperature  = 62°C

Unknown:

The heat needed to cause this temperature change = ?

Solution:

To solve this problem, we use the expression below:

       H = m c Ф  

H is the quantity of heat

m is the mass

c is the specific heat capacity

Ф is the temperature change

   So;

 Specific heat capacity of lead  = 130J/kg°C

 Insert the parameters and solve;

   H = 4.68 x 130 x (62 - 25) = 22510.8J