A negative charge of -0.00067 C and a positive charge of 0.00096 C are separated by 0.7 m. What is the force between the two charges?

-11,813.87N

Explanation:

According to coulombs law, the Force between the two charges is expressed as;

F = kq1q2/d²

k is the coulombs constant = 9*10⁹kg⋅m³⋅s⁻²⋅C⁻².

q1 = -0.00067 C

q2 = 0.00096 C

d  = 0.7m

Substitute into the formula:

F =  9*10^9 *  -0.00067 * 0.00096/0.7²

F = 9*10⁹*-6.7*10⁻⁴*9.6*10⁻⁴/0.49

F = -578.88*10⁹⁻⁸/0.49

F = -578.88*10/0.49

F = -5788.8/0.49

F = -11,813.87N

Hence the force between the two charges is -11,813.87N

f=ma newton

f=100x2.5=250n