4.A car completes at the maximum possible speed without sliding completes one lap in 14.3 s around a circular track with a radius of 50.0 m. What is the speed at which the car goes around the corner?

Given:
T =
R =
Unknown:
v=?
Equation:
v=2*pi*r/T

I HOPE THESE EXAMPLES HELP

A concrete highway curve of radius 80.0 m is banked at a 17.0 degrees. What is the maximum speed with which a 1800 kg rubber-tired car can take this curve without sliding? (Take the static coefficient of friction of rubber on concrete to be 1.0.  1000 kg car is going around a curve with radius 30 meters. If the coefficient of friction between the car's tires and the road is 0.5, what is the maximum speed at which the car can make the turn? Solution: mass of car, m = 1000 kg; radius of curve, r = 30 m; coefficient of friction, = 0.5; free-fall acceleration, g = 9.8 m/s 2

Explanation:

SORRY BUT I DONT UNDERSTAND THE SYMBOLE CAN YOU TRY A PICTURE

that would be because of both gravity and friction. so     c