How much extra water does a 147-lb concrete canoe displace compared to an ultra lightweight 36-lb Kevlar canoe of the same size carrying the same load

1.7791 ft^3

Explanation:

The computation of the extra water is as follows;

Here we use the following formula

Volume of the water = ÷ Weight of concrete canoe ÷ value of the weight of the specific water

= 147 lb ÷ 62.4 lb /ft^3

= 2.356 ft^3

Now the volume of water occupied in ultra lightweight

= 36 lb ÷ 62.4 lb /ft^3

= 0.5769 ft^3

Now the water volume displaced is

= 2.356 - 0.5769

= 1.7791 ft^3

probably not if net force is zero

i already answered it by 34/s