A block weighing 9.3 N requires a force of 3.7 N to push it along at constant velocity. What is the coefficient of friction for the surface

0.398

Explanation:

According to friction, the frictional force is directly proportional to the normal reaction

Ff = nR

Ff is the frictional force

n is the coefficient of friction

R is the reaction

Reaction is equal to the weight

R= W = 9.3N

Fm = Ff = 3.7N

Fm is the moving force

Get the coefficient of friction

n = Ff/R

n = 3.7/9.3

n = 0.398

Hence the coefficient of friction for the surface is 0.398

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge