A 3.00-g bullet has a muzzle velocity of 230 m/s when fired by a rifle with a weight of 25.0 N. (a) Determine the recoil speed of the rifle. 0.27 Correct: Your answer is correct. m/s (b) If a marksman with a weight of 650 N holds the rifle firmly against his shoulder, determine the recoil speed of the shooter and rifle. Incorrect: Your answer is incorrect.

0.27 m/s and 0.01 m/s

Explanation:

Given that

Mass of the bullet, m = 3 g = 0.003 kg

Velocity of the bullet, v = 230 m/s

Weight of the rifle, w = 25 N

From this, we know that the mass of the rifle, M = 25/9.8 = 2.55 kg

Using the law of conservation of momentum, we know that

Momentum of the gun = momentum of the bullet

M.g * V.g = m.b * v.b

2.55 * V.g = 0.003 * 230

2.55V.g = 0.69

V.g = 0.69 / 2.55

V.g = 0.27 m/s

If weight of the shooter = 650, then his mass = 650/9.8 = 66.33 kg

The recoil speed of the shooter is

0.69 / 66.33 = 0.010 m/s

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures