In a typical badminton swing the racket is in contact with the birdy for about 0.0010 seconds. If the 0.045kg birdy acquires a speed of 67 m/s, what is the force exerted by the racket on the ball

The force exerted by the racket on the ball is 3015 N.

The force exerted by the racket on the ball is given in the formula below.

⇒ Formula:

⇒ Where:

From the question,

⇒ Given:

⇒ Substitute these values into equation 1

Hence, The force exerted by the racket on the ball is 3015 N

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3015 N

Explanation:

From Newton's second law, we know that;

F.t = mv

F = force on the ball= ?

m= mass of the ball

v= velocity

F= mv/t

F= 0.045 × 67/0.0010

F= 3.015/0.0010

F= 3015 N

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s