A plane is traveling at a velocity of 90 m/s. It accelerates at a constant rate of 1.5 m/s2 until its velocity reaches 500 m/s. What distance did the plane cover while it was accelerating?

Recall that

v ² - v₀² = 2 a ∆x

where

v₀ = initial velocity

v = final velocity

a = acceleration

∆x = distance

Then

(500 m/s)² - (90 m/s)² = 2 (1.5 m/s²) ∆x

∆x = ((500 m/s)² - (90 m/s)²) / (2 (1.5 m/s²))

∆x ≈ 80,633 m

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation:

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