A 80 N horizontal force is applied to a 20.0 kg block at rest on a horizontal surface where µS = 0.6.? What is the magnitude of the force of friction on the block?

The frictional force on the block is 118 N.

Explanation:

Given;

horizontal force applied on the block, f = 80 N

mass of the block, m = 20.0 kg

coefficient of friction, μ = 0.6

The frictional force on the block is calculated as;

F = μR

F = μ(mg)

F = 0.6(20 x 9.81)

F = 117.7 N

F = 118 N.

Therefore, the frictional force on the block is 118 N.

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