How many times greater is the intensity of a 35-db sound compared to a 25-db sound?

10 Times (greater)

Explanation:

The given parameters are;

The number of decibels of the first sound, 35-db

The number of decibels of the second sound, 25 db

We have;

Where;

I₀ = 10⁻¹² W/m² = The lowest perceivable sound

Therefore, we have;

Substituting the known values, gives;

When β = 35-db, we get;

When β = 25-db, we get;

Therefore, we get the number of times the intensity of a 35-db sound is compared to a 25-db sound, which is, I₃₅/I₂₅ is given as follows;

Therefore, the intensity of a 35-db sound is 10 times greater than the intensity of a 25-db sound

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