A Shaolin monk of mass 60 kg is able to do a ‘finger stand’: he supports his whole weight on his two index fingers, giving him a total contact area of 4 cm 2 with the ground. Calculate the pressure he exerts on the ground (include units), and write your answer to two significant figures.

P = 1471500 [Pa]

Explanation:

We must remember that pressure is defined as the relationship between Force over the area.

where:

P = pressure [Pa] (units of pascals)

F = force [N] (units of Newtons)

A = area of contact = 4 [cm²]

But first we must convert from cm² to m²

A = 0.0004 [m²]

Also, the weight should be calculated as follows:

where:

m = mass = 60 [kg]

g = gravity acceleration = 9.81 [m/s²]

Now replacing:

And the pressure:

Because 1 [Pa] = 1 [N/m²]

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