What force (in N) must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2100 kg car (a large car) resting on the slave cylinder

Complete Question:

What force (in N) must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2100 kg car (a large car) resting on the slave cylinder ? The master cylinder has a 2.00-cm diameter and the slave has a 24.0-cm diameter

Explanation:

Given

--- mass

--- diameter of the large cylinder

--- diameter of the slave cylinder

To do this, we apply Archimedes' principle of buoyancy which implies that:

Where

Calculating the area of the master cylinder.

Calculating the area of the slave cylinder.

Substitute these values in:

Multiply both sides by

The force exerted on the slave cylinder (F2) is calculated as:

Substitute 20580 for F2 in

Hence, the force exerted on the master cylinder is approximately 142.92N

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