Ball 1 of mass m travels at a velocity of v m/s south and collides with Ball 2 of mass 3m which is travelling at a velocity of v/2 north. If the final velocity of ball 1 is v/4 north, what is the final velocity of ball 2

2/3v m/s

Explanation:

Given that

Mass of ball 1 = m

Initial velocity u1 of ball 1 = v m/s

Mass of ball 2 = 3m

Initial velocity u2 of ball 2 = v/2 m/s

Final velocity v1 of ball 1 = v/4 m/s

Final velocity v2 of ball 2 = ?

To solve this question, we will be applying the law of conservation of momentum, which is mathematically given as

m1u1 + m2u2 = m1v1 + m2v2

If we substitute the given values directly, we have

m * v + 3m * v/2 = m * v/2 + 3m * v2

mv + 3mv/2 = mv/2 + 3m * v2, collecting like terms, we have

mv + 3mv/2 - mv/2 = 3m * v2

mv + 2mv/2 = 3m * v2

mv + mv = 3m * v2

2mv = 3m * v2, dividing both sides by 3m

v2 = 2mv/3m

v2 = 2/3v

Therefore, the final velocity v2 of ball 2 is 2/3v

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this