0.100-kilogram apple falls from a height of 1.50 meters to 1.00 meters. ignoring frictional effects, what is the kinetic energy of the apple at this height?

0.00 j
0.49 j
0.98 j
1.47 j

Kinetic energy of the apple is 0.49 J.            

Explanation:

It is given that,

Mass of the apple, m = 0.1 kg

Initial height, h = 1.5 m

Final height, h' = 1 m

Let K is the kinetic energy of the apple at this height. We can use the conservation of energy to find it. As the height decreased the potential energy gets converted to the kinetic energy. It is given by :

K = -0.49 J

So, the energy of the apple at this height is 0.49 J. Hence, this is the required solution.

a) are muscles that have bands.

happy to

pls mark as brainliest

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s