A rifle is aimed horizontally at the center of a large target 60 m away. The initial speed of the bullet is 240 m/s. What is the distance from the center of the target to the point where the bullet strikes the target

The distance from the center of the target to the point where the bullet strikes the target is 0.31 m.

Explanation:

Given;

the position of center of the target, x₀ = 60 m

initial velocity of the bullet, u = 240 m/s

The time the bullet strikes the center of the large target is calculated as;

The distance from the center of the target to the point where the bullet strikes the target is calculated as;

x = vt + ¹/₂gt²

where;

v is the final velocity of the bullet when it strikes the target = 0

x = 0 + ¹/₂(9.8)(0.25²)

x = 0.31 m

Therefore, the distance from the center of the target to the point where the bullet strikes the target is 0.31 m.

a.) travels faster in solids because the particles are closer together.

air is a gas water is a liquid

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.