How far must you stretch a spring with k = 1800 N/m to store 270 J of energy? Express your answer in meters.

0.55m

Explanation:

Given parameters:

Spring constant  = 1800N/m

Elastic potential energy  = 270J

Unknown:

extension = ?

Solution:

To solve this problem, we use the formula of the elastic potential energy;

     E. P  = k e²  

E.P is the elastic potential energy

k is the spring constant

e is the extension

            270  =   x 1800 x e²  

                e  = 0.55m

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explanation: