When a 1.7 m tall man stands, his brain is 0.5 m above his heart. If he bends so that his brain is 0.4 m below his heart, by how much does the blood pressure in his brain

changes? Note: PHeart=13.3x103

Pa.

9.54 Kpa

Explanation:

Given :

Pheart = 13.3 * 10^3

Density of blood (ρ) = 1060 kg/m³

Difference in height of brain and heart in standing position = - 0.5

Difference in height of Brain a d heart in bending position = 0.4

g = acceleration due to gravity = 10 m/s²

Blood pressure of brain in standing position:

Pheart + ρ*g(-0.5)

13.3 * 10^3 + 1060 * 10 * - 0.5

13300 - 5300 = 8000 pascal = 8Kpa

Blood pressure of brain in bending position:

Pheart + ρ*g(0.4)

13.3 10^3 + 1060 * 10 * 0.4

13300 + 4240 = 17540 Pa = 17.54 Kpa

17.54Kpa - 8Kpa

= 9.54 Kpa

low freq = 100 mhz

low wavelength =101.7m

length = 3x10^8/freq

your answer is c! hope this : )