What is the electric potential at a distance of 1.2 m from a 7.5 UC point charge? 5.6 x 104 v
8.1 x 104 V
5.6 % 1010 V
8.1 x 1010 V

5.6x10^4

Explanation:

use the equation V=kq/d

k is the constant 8.99x10^9

V=(8.99x10^9)q/d

q is the charge, 7.5 micro coulombs, but to get coulombs, multiply by 10^-6

V=(8.99x10^9)(7.5x10^-6)/d

And from the problem, we know that the distance is 1.2 meters

V=(8.99x10^9)(7.5x10^-6)/1.2

This simplifies to 5.6x10^4

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

d) physical means can be used to separate the components of air.