Two small nonconducting spheres have a total charge of (a) When placed 28.0 cm apart, the force each exerts on the other is 12.0 N and is repulsive. What is the charge on each

q = 1 x 10⁻⁵ C = 10 μC

Explanation:

The repulsive  force between the charges is given by Coulumb's Law:

where,

F = Electrostatic Force = 12 N

k = Coulomb's Constat = 9 x 10⁹ Nm²/C²

r = distance between charges = 28 cm = 0.28 m

Since the values or charges are not given. We assume that both charges have same mahnitude. Therefore,

q₁ = q₂ = q = charge on each sphere = ?

Therefore,

q = 1 x 10⁻⁵ C = 10 μC

frequency or wavelenth of em radiation in a vacuum