An ice-hockey player weighing 900 N is skating with a velocity of 8.0 m/s when they slam into a member of the opposing team who is standing still. They become tangled together and move down the ice with a velocity of 5.0 m/s. What is the mass of the other player

Mass of player 2 is 55.044kg

Explanation:

Step one:

given data

Weight of player 1= 900 N

mass= weight/acceleration due to gravity

mass of player= 900/9.81

m1= 91.74kg

v1= 8m/s

mass of player 2

m2= ?

v2= 0m/s

Step two:

from the problem description, after impact, they both moved with a common velocity of V= 5m/s, hence the collision is an inelastic collision

the expression for inelastic collision is

m1v1+m2v2=(m1+m2)V

substitute

91.74*8+m2*0=(91.74+m2)5

733.92=458.7+5m2

275.22=5m2

divide both sides by 5

m2=275.22/5

m2=55.044kg

The weight of player two is

=55.044*9.81

=539.98N

d) physical means can be used to separate the components of air.