For both circuits: Determine the potential difference on and the current through each resistor. Show your work and then check your answer with PhET

Answer is explained in the explanation section below.

Explanation:

Note: This question is incomplete and lacks the necessary diagram of the circuits to solve for this question. However, I have found similar question on the internet and dragged the diagrams out of it. I have attached the diagrams of the circuits for your ease. It has two circuits to be solved. Attachment 1 refers to first circuit and Attachment 2 refers to second circuit.

Solution:

We are asked to find the potential difference and current through each resistor.

So,

Calculations for Circuit 1: Please refer to Attachment 1

First we need to find the Resistance:

Req =

R = 6.6 Ohm

Now, we know that:

V = IR

So,

I = V/R

V = 12 V

I = 12 V/ 6.6 ohm

I = 1.82 Amperes.

Now,

The Potential Difference through 3 ohm resistor:

P.D = = 1.82 x 3

= 5.45 V

Now,

The Potential Difference through 6 ohm and 9 ohm resistor:

=  12V - 5.45V

=  6.545V

Now,

The current through 6 ohm is:

=

= 1.09 A

Now,

The Current through 9 ohm is:

 =

 = 0.72 A

Similarly,

Calculations for Circuit 2: Please refer to attachment 2:

Req =

Req = 62.35 ohm

I = V/R

I = 12 V/ 62.35ohm

I = 0.192 Amperes.

Now,

The The Potential Difference through 20 ohm resistor:

= 20 x 0.192

= 3.849 V

Now,

The The Potential Difference through 90 ohm resistor:

= 12 - 3.849

= 8.150

Now,

The Current through 90 ohm is:

 = 8.1509/90

= 0.0905 Amperes

Now,

The Current through 30 and 50 ohm is:

= 0.192 - 0.0905

 = 0.101 A

Now,

The Potential Difference through 50 ohm resistor:

= 50 x 0.101

 = 5.094 V

The Potential Difference through 30 ohm resistor:    

= 30 x  0.101

= 3.0566 V

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000