A roller coaster car starts at 6 m/s at the top of the hill at the 3 seconds latter at the bottom of the hill the roller coaster car is going 72 m/s, what was the cars acceleration?

22m/s

Explanation:

Step one:

Given data

Initial velocity of roller coster u= 6 m/s

Final velocity v= 72m/s

time t= 3 seconds

Required

We want to solve for the acceleration of the roller coster

Step two:

From the formula

acceleration= v-u/t

substitute

a= 72-6/3

a=66 /3

a= 22 m/s

The cars acceleration 22m/s

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