An inclined plane is set at an angle of 29 degrees above horizontalWhat is the acceleration of a 420 g block of ice sliding down the inclined plane? Assume no friction

The net force parallel to the plane is

∑ F = m g sin(29°) = m a

where

m = mass of the block

g = magnitude of the acceleration due to gravity, 9.8 m/s²

a = mag. of acceleration of the block

where we take the direction of the block's sliding down the plane to be positive. Then

a = g sin(29°) ≈ 4.8 m/s²

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.