a boat is moving across a lake during a race at a rate of 63m/s^2 and reaches a velocity of 96m/s. how long did it take the boat accelerate?

1.52s

Explanation:

Given parameters:

Acceleration  = 63m/s²

Final velocity  = 96m/s

Unknown:

Time taken  = ?

Solution:

To solve this problem, we use one of the kinematics equation:

        v  = u + at

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

So;

           96  =  0 + 63t

             t  = 1.52s

ok

explanation:

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west