The net electric flux through a cubic box with sides that are 22.0 cm long is 4950 N⋅m2/C . What charge is enclosed by the box?

43.83 nC

Explanation:

We know Q = ε₀Ψ where Q = charge enclosed by the cubic box,  ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m and Ψ = net electric flux through cubic box = 4950 Nm²/C

So, substituting the values of the variables into the equation, we have

Q = ε₀Ψ

= 8.854 × 10⁻¹² F/m × 4950 Nm²/C

= 43827.3 × 10⁻¹² C = 4.38273 × 10⁻⁸ C

= 43.8273 × 10⁻⁹ C

= 43.8273 nC

≅ 43.83 nC

0.863333

86%

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