A child approaches a stop sign and applies the brakes to slow to a stop. If the bicycle and child were originally traveling at 9.00 m/s and the breaks cause a deceleration of magnitude 1.20 m/s^2, how long will it take the child to stop?

7.5secs

Explanation:

Using the equation of motion

v = u + at

v is the final velocity = 0m/s

u is the initial velocity = 9m/s

a is the deceleration = -1.2m/s²

t is the required time

Substitute;

0 = 9 + 1.2(t)

-9 = -1.2t

t = -9/-1.2

t = 7.5secs

hence it takes the child 7.5secs to stop

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