Answers: 1
![A=\frac{70W}{0.0089\frac{w}{m^{2} } } \\\\A=7865.16[m^{2} ]](/tpl/images/1061/8248/f2f30.png)
![A=\pi *r^{2} \\7865.16=\pi *r^{2} \\\\r=\sqrt{\frac{7865.16}{\pi } } \\r=50[m]](/tpl/images/1061/8248/d03d6.png)
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If the power output for an instrument is 70.0W find the distance where the intensity is 0.0089 W/m2?...
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