You kick a soccer ball with a speed of 12 m/s at an angle of 21. How long does it take the ball to reach the top of its trajectory?

Time, t = 0.439 seconds

Explanation:

Given the following data;

Angle, x = 21°

Initial velocity, u = usinx = 12Sin21° = 4.3004m/s

We know that acceleration due to gravity is equal to 9.8m/s

Final velocity = 0m/s since it reached its highest trajectory.

To find the time, we would use the first equation of motion;

V = U + gt

0 = 4.3004 + (-9.8)t

0 = 4.3004 - 9.8t

9.8t = 4.3004

t = 4.3004/9.8

t = 0.439 seconds

Therefore, it will take the ball 0.439 seconds to reach the top of its trajectory.

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