Estimate the radial acceleration (m/s2) of the toe at the end of the horizontally extended leg of a ballerina doing a pirouette. Assume the length of ballerina's leg to be 0.80 m. Suppose that she completes a full turn in 1.0 s. Determine its acceleration during this launch

The acceleration during this launch is approximately 31.583 meters per square second.

Explanation:

Let suppose that the ballerina rotates at constant rate. The radial acceleration of the toe at the end of the horizontally extended leg of the ballerina doing a pirouette (), measured in meters per square second, is determined by the following formula:

(1)

Where:

- Radius, measured in meters.

- Period, measured in seconds.

If we know that and , then the radial acceleration of the ballerina is:

The acceleration during this launch is approximately 31.583 meters per square second.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

c. magnitude and direction