A certain compact disc (CD) contains 783.216 megabytes of digital information. Each byte consists of exactly 8 bits. When played, a CD player reads the CD's information at a constant rate of 1.5 megabits per second. How many minutes does it take the player to read the entire CD? Express your answer using two significant figures

69.62 minutes

Explanation:

From the information we have here,

1 byte is = 8 bits

So 1 megabyte = 8 megabits

Then

783.216 x 8 megabits = 6265.728 megabits

This player has its reading capacity at 1.5 megabits / second

So 1 minute = 60x1.5

= 90 megabits / min

Then we have the entire reading time of this CD player to be =

6265.728/90

= 69.62 minutes.

This answers the question

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.