Two metal disks, one with radius R1 = 2.50 cm and mass M1 = 0.800 kg and the other with radius R2 = 5.00 cm and mass M2 = 1.70 kg, are welded together and mounted on a frictionless axis through their common center. What is the total moment of inertia of the two disks?

I = 2.375 × 10-³ Kgm²

Explanation:

Using the formulas to calculate the moment of inertia of a solid cylinder:

I = ½MR²

Where;

I = moment (kgm²)

M = mass of object (Kg)

R = radius of object (m)

Total moment of inertia of the two disks is expressed as: I = I(1) + I(2)

That is;

I = ½M1R1 + ½M2R2

According to the provided information;

R1 = 2.50cm = 0.025m

M1 = 0.800kg

R2 = 5.00cm = 0.05m

M2 = 1.70kg

I = (½ × 0.800 × 0.025²) + (½ × 0.05² × 1.70)

I = (½ × 0.0005) + (½ × 0.00425)

I = (0.00025) + (0.002125)

I = 0.002375

I = 2.375 × 10-³ Kgm²

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