The force of gravity acting on an object is 300 N. What is the mass of the object?

Explanation:

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Explanation:

uppose you want to calculate the size of the gravitational force acting between you and your colleague as you approach each other (one metre apart) in the corridor. We can do this quite simply by using Newton's equation: forcegravity =  

G  ×  M  ×  m

separation2

.

Suppose: your mass, m, is 60 kilogram; the mass of your colleague, M, is 70 kg; your centre-to-centre separation, r, is 1 m; and G is 6.67 × 10-11 newton square metre kilogram-2.

Inserting these values into the equation to get 6.67 × 10-11 newton square metre kilogram-2  ×  

60 kilogram  ×  70  kilogram

1 metre2

. You can work out this force and you'll get 2.8 × 10-7 newton.

In other words you exert a gravitational pulling force of 0.28 millionths of a newton on your colleague! The force exists but it is too small to notice in practice.

From the numbers it is clear that because the value of G is so small, the magnitude of the gravitational force will be very small, unless one or other of the objects has a very large mass.

You can use Newton's equation to check out the empirical observation that a 1 kilogram mass experiences a gravitational pull of about 10 N at the surface of the Earth. This is calculating the gravitational pull at the Earth's surface

forcegravity =  

G  ×  M  ×  m

separation2

Where: mass, m, is 1 kilogram; mass of the Earth, M, is 6.0 × 1024 kilogram; the radius of the Earth (separation of masses), r, is 6.4 × 106 m; and G is 6.67 × 10-11 newton square metrekilogram-2}.

Inserting these values into the equation, and work this out to get a force of 9.8 newton .

As expected, the pull of the Earth on a 1 kilogram mass at its surface is about 10 N .

what is the question because that is not a question.